(440*(2^x-1))/(2^x+36)=60

Solution for (440*(2^x-1))/(2^x+36)=60 equation:

(440(2^x-1))/(2^x+36)=60

We move all terms to the left:

(440(2^x-1))/(2^x+36)-(60)=0


Domain of the equation: (2^x+36)!=0

We move all terms containing x to the left, all other terms to the right

2^x!=-36

x!=-36/1

x!=-36

x∈R


We multiply all the terms by the denominator


(440(2^x-1))-60*(2^x+36)=0


We calculate terms in parentheses: +(440(2^x-1)), so:

440(2^x-1)

We multiply parentheses

880x-440

Back to the equation:

+(880x-440)


We multiply parentheses

(880x-440)-120x-2160=0

We get rid of parentheses

880x-120x-440-2160=0

We add all the numbers together, and all the variables

760x-2600=0

We move all terms containing x to the left, all other terms to the right

760x=2600

x=2600/760

x=3+8/19